Examples

How does CO2mmon work?

Common applies the “1 Greencent for 1 kg of non-emitted CO2” principle to data we measure in various sectors from various sources.

Two criteria are considered when tracking rides: distance and means of transportation. Users emit no CO2 when cycling and 12 g per km when riding a tram for instance. So, when riding a tram for 5 km, a user emits 60 g of CO2. We take then the 138 g of CO2 which are emitted by a car per km in urban areas, we calculate the difference, convert the spared CO2 into Greencents and allocate them to the user. For example, for the 5 km in tram: (138 – 60) x 5 = 390. The user spared 390 g of CO2, so she gets 0.39 GC as a GC stands for 1 kg of non-emitted CO2 and 390 g = 0.39 kg.

Cycling in urban areas

Examples

In the food sector
Meals and products are evaluated first according to four criteria: mass, type, origin and production mode (organic or conventional) of each ingredient. For example, a curry made of vegetables and yogurt weighing 330 g would have a CO2 footprint of 0.92 kg. Then we compare this result with other meals and products of the same category, for example main dishes, and we attribute Greencents to meals the CO2 footprint of which is below the average.

In the electricity sector
Electricity can be generated out of various sources: coal, nuclear, gas, wind, sun, hydrogen, tidal, geothermal, hydropower etc. Each of these sources have a different CO2 footprint and can also be tracked; this is why consumers can specifically choose to use green electricity and pay a premium for it. The carbon footprint in the electricity sector is called CO2 emission intensity and expressed in grams of carbon dioxide per kilowatt hour of electricity for final consumption (g CO2/kWh). The average CO2 footprint of electricity in Germany is currently 380 g CO2/kWh. If a user consumes 10 kWh of solar electricity for instance, he would generate a carbon footprint which is below the average and would thus be rewarded by calculating the difference between his CO2 emissions intensity and the average one. He would spare: (380 – 48) x 10 = 3320 g of CO2, so he would get 3.32 GC.